1.75x^2+4X-125=0

Solution for 1.75x^2+4X-125=0 equation:

1.75x^2+4x-125=0

a = 1.75; b = 4; c = -125;
Δ = b2-4ac
Δ = 42-4·1.75·(-125)
Δ = 891
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{891}=\sqrt{81*11}=\sqrt{81}*\sqrt{11}=9\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-9\sqrt{11}}{2*1.75}=\frac{-4-9\sqrt{11}}{3.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+9\sqrt{11}}{2*1.75}=\frac{-4+9\sqrt{11}}{3.5}
$